Question

найти значение выражения: arcsin1/2+arctg (-(корень3)/3+3 arccos (-1/2)

Answer 1

π/6 - arctg (√3/3) + 3(π - arccos (1/2))=
= π/6 - π/6 + 3(π - π/3) =
= 3*2π/3 = 2π