Question

Помогите со вторым номером

Answer 1

$left(frac{x}{e^x+1}right)' = frac{e^x+1 - xe^x}{(e^x+1)^2} = frac{1+(1-x)e^x}{(e^x+1)^2}$

Answer 2

y`=[x`(e^x+1)-x(e^x+1)`]/(e^x+1)²=(e^x+1-x*e^x)/(e^x+1)²