Question

cos (2x+π/6)+1=0
помогите пожалуйста

Answer 1

cos (2x+π/6)+1=0

cos (2x+π/6)=-1

2x+π/6=π+2πn, n∈Z
2x+π/6=-π+2πn, n∈Z

2x=π-π/6+2πn, n∈Z
2x=-π-π/6+2πn, n∈Z

2x=5π/6+2πn, n∈Z
2x=-7π/6+2πn, n∈Z

x=5π/12+πn, n∈Z
x=-7π/12+πn, n∈Z

Ответ: -7π/12+πn, n∈Z; 5π/12+πn, n∈Z