Question

Разложите на множители:
2) 2y^3 - 8y
4) 2/3x^3 - 8/27 x
6) 7y^5 - 7/4y^3

Answer 1

$2y^3 - 8y = 2y(y^2-4) = 2y(y-2)(y+2) \ \ (frac{2}{3} )^3 - frac{8}{27x} = frac{8}{27} - frac{8}{27x} = frac{8x-8}{27x}$