Question

(4х-7)(5х+1)=(10х-3)(2х+4)+5



найти икс

Answer 1

(4х-7)(5х+1)=(10х-3)(2х+4)+5
20x²+4x-35x-7=20x²+40x-6x-12+5
4x-35x-40x+6x=-12+5+7
-65x=0
x=0