Question

у=-2cos3x+1. Найдите значения f(π), f(π/4), f(-π/3), f(0)

Answer 1

f(pi)=-2*-1+1=3 f(pi/4)=-2*(-sqrt2/2)+1= sqrt2+1 f(-pi/3)=-2*-1+1=3 f(0)=-2*1+1=-1

Answer 2

y=-2cos3x+1
y(π)=-2cos3π+1=-2cosπ+1=-2*(-1)+1=2+1=3
y(π/4)=-2cos3π/4+1=-2*(-√2/2)+1=√2+1
y(-π/3)=-2cos(-π)+1=-2*(-4)+1=2+1=3
y(0)=-2cos0+1=-2*1+1=-2+1=-1