Question

ребят пожалуйста очень срочно

Answer 1

$1.1)x^2*x^8=x^{2+8}=x^{10};$
$1.2)(y^2)^3*y^{10}=y^{3*2}*y^{10}=y^6*y^{10}=y^{6+10}=y^{16};$
$1.3) frac{x^{12}yx^3}{(x^4y)^2}= frac{x^{12}yx^3}{x^{4*2}y^2}= frac{x^{15}y}{x^8y^2}=frac{x^{15}y}{x^8y^2}= frac{x^7}{y};$
$2.1)-a^2*(-1,5)b*4b^3a=1,5a^2b*4b^3a=6a^3b^4-$ степень $4$
$2.2)(-1,25x^6)*8x(y^5)^6=-10x^7y^3^0$ - степень $30.$
$3)2a^2*b*25*ab^2=2a^3b^3*25=2* (frac{1}{4})^3*4^3*25=2* frac{1}{64}*64*25=$ $2*25=50;$
$4.1) frac{(7^5)^3}{7^{13}*49}= frac{7^{15}}{7^{13}*7^2}= frac{7^{15}}{7^{15}}=1;$
$4.2) frac{50^3}{(2^2)^3*5^6}= frac{(25*2)^3}{2^6*5^6}= frac{(5^2*2)^3}{2^6*5^6}= frac{5^6*2^3}{2^6*5^6}= frac{1}{2^3}= frac{1}{8}=0,125;$
$2.3) frac{(-15)^4*75}{3^4*5^2*25}= frac{(5*3)^4*3*5^2}{3^4*5^2*5^2}= frac{5^4*3^4*3}{3^4*5^2}= frac{5^2*3^5}{3^4}= frac{25*3}{1}=75;$
$5)-3 frac{1}{5}x^7y^9*(- frac{1}{2}x^2y^8)^3*12,5x^3=$
$=-3,2x^7y^9*(-0,125x^6y^{24})*12,5x^3=0,4x^{13}y^{33}*12,5x^3=5x^{16}y^{33};$