Question

Помогите пожалуйста. sqrt 6+4x-x^2 = 4-x

Answer 1

$sqrt{6+4x-x^2}= 4-x \ (sqrt{6+4x-x^2})^2 = (4-x)^2 \ 6+4x+x^2=16-8x+x^2 \ 6+4x=16-8x \ 4x+8x=16-6 \ 12x = 10 \ x=frac{5}{6}$