Question

2log3x=1 + log3(2x-3)

Answer 1

2log3x=1 + log3(2x-3)     ОДЗ: x>3/2

log3(x)²=log3(3)+ log3(2x-3)

log3(x)²=log3(3·(2x-3))

x²=6x-9

x²-6x+9=0  ⇔  (x-3)²=0

Корень уравнения x=3