Question

решить уравнение 2 cos^x -cosx-1=0

Answer 1

cosx=t, 2t^2+t-1=0, t1=-1, t2=1/2. cosx=-1, x=n+2nk, cosx=1/2, x=+-arccos(1/2)+2nl, lєZ, x=+-n/3+2nl, lєZ