Question

(2x-5)2(два вторая степень)-(2x- 3)(2x+3)=0

Answer 1

(2x-5)^2=(2x-3)(2x+3)
4x^2-2*2x*5+25=4x^2-9
4x^2-20x+25=4x^2-9
-20x+25=-9
-20x=-34
x=1.7