Question

Решите уровнения 1) (х-4)х^2+2(х-4)=0, 2) 25+20х+4х^2=0

Answer 1

К сожелению первый не смог

Answer 2

$(x-4)x^2+2(x-4)=0, \ (x-4)(x^2+2)=0, \ left [ {{x-4=0,} atop {x^2+2=0;}} right. left [ {{x=4,} atop {x^2=-2;}} right. left [ {{x=4,} atop {xinvarnothing;}} right. \ x=4.$

$25+20x+4x^2=0, \ 5^2+2cdot5cdot2x+(2x)^2=0, \ (5+2x)^2=0, \ 5+2x=0, \ 2x=-5, \ x=-2,5.$