Question

log9 81+log0.5 0.25-4^log2 5

Answer 1

$log_9 81+log_{0.5} 0.25- 4^{ log_{2}5 } =log_9 9^2+log_{0.5} 0.5^2- 2^{ 2log_{2}5 } =$$=2+2-2^{ log_{2}5^2 }=4-25=-21$