Question

(y^2-25/6y-30)=0
(-y^2+16/-3y-12)=0

Answer 1

у^2-25/6у-30=(у-5)(у+5)/6(у-5)=у+5/6
-у^2+16/-3у-12=-(у^2-16)/-3(у+4)=(у-4)(у+4)/3(у+4)=у-4/3