Question

2 log 72 3 + 3 log 72 2.+ 6

Answer 1

$2log_{72}3+3log_{72}2+6=log_{72}3^2+log_{72}2^3+6=\=log_{72}9+log_{72}8+6=log_{72}9cdot8+6=log_{72}72+6=1+6=7$