Question

(tg 2x-3)(2cos x/3+1)=0

С решением

Answer 1

(tg2x-3)(2cos x/3+1)=0
tg2x-3=0
tg2x=3
2x=arctg3+пn,n€z
x=1/2arctg3+пn/2,n€z
2cos x/3+1=0
cos x/3=-1/2
x/3=±(п-arccos1/2)+2пn,n€z
x/3=±2п/3+2пn,n€z
x=±2п+6пn,n€z