Question

(х+2)(х-2)+7=(х-3)в квадрате+1

Answer 1

$(x+2)(x-2)+7=(x-3)^2+1 \ x^2-4+7=x^2-6x+9+1 \ x^2-x^2+6x=9+1+4-7 \ 6x=7 \ x= frac{7}{6}=1 frac{1}{6}$