Question

log0.25(x^2+6x)=-2 решите плиз

Answer 1

log0.25(x^2+6x)=-2
ОДЗ: x∈(-∞;-6)∪(0;+∞)
0,25^(-2) = x^2+6x
x^2 + 6x - 16 = 0
D = 36 + 64 = 100
x1 = (-6-10)/2 = -8
x2 = (-6+10)/2 = 2