Question

lim x→∞ ln(1+e^2x)/x
хеелп ребя

Answer 1

$lim_{x to infty} frac{ln(1+e^{2x})}{x} =[ frac{infty}{infty} ] = lim_{x to infty} frac{2e^{2x}}{1+e^{2x}}=[ frac{infty}{infty} ] = lim_{x to infty} frac{4e^{2x}}{2e^{2x}}=2$