Question

(х+5)у квадрати+(х-8)(х+8)+(3х-4)(2х+2)

Answer 1

$(x+5)^2+(x-8)(x+8)+(3x-4)(2x+2)= \ =x^2+10x+25+x^2-64+6x^2+6x-8x-8=8x^2+8x-47$

Answer 2

(х+5)^2+(х-8)(х+8)+(3х-4)(2х+2)=х^2+10х+25+х^2-64+6х^2+6х-8х-8=8х^2+8х-47.