Question

найти dy/dx
$5 ^{cos^{3} 2x^{2} }$

Answer 1

$frac{dy}{dx} =5 ^{cos^{3} 2x^{2} } *ln5*(cos^{3} 2x^{2} )'= \ =5 ^{cos^{3} 2x^{2} } *ln5*3cos^22x^{2}*(cos2x^{2} )'= \ =5 ^{cos^{3} 2x^{2} } *ln5*3cos^22x^{2}*(-sin2x^{2})*(2x^{2} )'= \ =5 ^{cos^{3} 2x^{2} } *ln5*3cos^22x^{2}*(-sin2x^{2})*4x = \ =-12xln5*5 ^{cos^{3} 2x^{2} } sin2x^{2} cos^22x^{2}$