Question

(3n-2m)^3 представить в виде многочлена

Answer 1

(a^3-b^3)=a^3-3*a^2*b+3*a*b^2-b^3➡
3n^3- 3*3n^2*2m+3*3n*2m^2-2m^3

Answer 2

27n^3-3(18n^2m)+3(12nm^2)-8m^3=
27n^3-54n^2m+36nm^2-8m^3