Question

Log3(6+7x)=log3(1-x)+1

Answer 1

6+7х=1-х
7х+х=1-6
8х=-5
х=-0,625

Answer 2

$log_3(6+7x)=log_3(1-x)+1$
$log_3(6+7x)=log_3(1-x)+1, x neq (- frac{6}{7} ,1)$
$log_3(6+7x)=log_3(1-x)+log_33$
$log_3(6+7x)=log_3((1-x)*3)$
$log_3(6+7x)=log_3(3-3x)$
$6+7x=3-3x$
$x=- frac{3}{10} , x neq (- frac{6}{7} ,1)$
$x=- frac{3}{10} =-0,3$
Ответ: -0,3