Question

Решить систему уравнений { 2х-у = 5; { х^2 + у + 2 = 0

Answer 1

$left { {{2x - y = 5} atop { x^{2} + y + 2 = 0}} right.$
$left { {{y = 2x - 5} atop { x^{2} + 2x - 5+ 2 = 0}} right.$
$left { {{y = 2x - 5} atop { x^{2} + 2x - 3= 0}} right.$
$left { { left { {{ x_{1} = 1} atop { y_{1} = -3 }} right. } atop { left { { x_{2} = -3 } atop { y_{2} = -11}} right. }} right.$