Question

Найдите первые 8 членов последовательности an = 2n - 2

Answer 1

a₁ = 2 · 1 - 2 = 0
a₂ = 2 · 2 - 2 = 2
a₃ = 2 · 3 - 2 = 4
a₄ = 2 · 4 - 2 = 6
a₅ = 2 · 5 - 2 = 8
a₆ = 2 · 6 - 2 = 10
a₇ = 2 · 7 - 2 = 12
a₈ = 2 · 8 - 2 = 14