Question

a/(x+1)+(bx+c)/(x^2-x+1)=1/(x^3+1)

Answer 1

A/(x+1)+(bx+c)/(x²-x+1)=1/(x+1)(x²-x+1)
x≠-1
A(x²-x+1)+(bx+c)(x+1)=1
Ax²-Ax+A+bx²+bx+cx+c=1
x²(A+b)+x(b+c-A)+(A+c)=1
{A+b=0⇒A=-b
{b+c-A=0⇒2b+c=0⇒c=-2b
{A+c=1⇒-b-2b=1⇒-3b=1⇒b=-1/3
A=1/3
c=2/3

Answer 2

Спасибо!!!!:):):)Thanks!!!