Question

4x(16-8x+x^2)=7(4-x)
помогите с уравнением

Answer 1

4x (4 - x)^2 - 7(4 - x) = 0 
(4 - x)(4x (4 - x) - 7) = 0 

1) 4 - x = 0
- x = - 4 
x = 4 

2) 16x - 4x^2 - 7 = 0 
4x^2 - 16x + 7 = 0 
D = 144 = 12^2
x2 = ( 16 + 12)/8 = 3,5
x3 = ( 16 - 12)/8 = 0,5

Ответ
0.5; 3.5; 4

Answer 2

$4x(16-8x+ x^{2} )=7(4-x); 4x( 4-x)^{2} -7(4-x);(4x(4-x)-7)*$
$*(4-x); left { {{-4 x^{2} +16x-7=0} atop {4-x=0}} right. x[tex] x_{1}= frac{-16+12}{-8} =0.5; x_{2} = frac{-16-12}{-8} =3.5; x_{3} =4$ =4; D= 16^{2}-4*(-4)*(-7)= 12^{2} [/tex]