Question

Прошу, очень надо, 33 балла
$a) 15^{2-log(15)9}$
$b) 2log(1/5)5+log(1/5)3+0.5log(1/5)225$
$c) 49^{log(7)2+log(sqrt{7})2-1/2log(49)64}$

Answer 1

15^(2-log(15)9)=15²:15^log(15)9=225:9=25

2log(1/5)5+log(1/5)3+0,5log(1/5)225=log(1/5)25+log(1/5)3+log(1/5)15=
=log(1/5)(25*3*15)=log(1/5)(125*9)=log(1/5)125+log(1/5)9=-3+2log(1/5)3

49^(log(7)2+log(√7)2-1/2*log(49)64)=
=49^(log(7)2)* 49^(log(√7)2):49^(1/2*log(49)64))=
7^(log(7)4 *(√7)^log(√7)16 : 49^log(49)8=4*16:8=8