Question

найдите корни уравнений 38(0,1x+1)=40-3,2x

Answer 1

38(0,1x+1)=40-3,2x
3,8x+38=40-3,2x
3,8x+3,2x=40-38
7x=2
x=2/7

Answer 2

38(0,1x+1)=40-3,2x
3,8х+38=40-3,2х
3,8х+3,2х=40-38
7х=2
Х=2/7

Answer 3

Оо