Question

Решите систему уравнений:
{x-y=pi/2
{sinx+cosy=0

Answer 1

x = y + π/2
sin(y + π/2) + cosy = 0

x = y + π/2
cosy + cosy = 0

x = y + π/2
cosy = 0

x = y + π/2
y = π/2 + πk, k€Z

x = π/2 + π/2 + πk
y = π/2 + πk, k€Z

x = π + πk
y = π/2 + πk, k€Z

Ответ: (π + πk; π/2 + πk), где k€Z.