Question

обчислити: -4arccos(-√2/ 2 )+3arcsin1/2-arctg(-1)

Answer 1

-4arccos (-√2|2)+3 arcsin1|2-arctg(-1)= -4(π-arccos√2/2)+3*π/6-(-arctg1)=

= -4(π-π/4)+π/2+π/4= -4 *3π/4+π/2+π/4= -9π/4