Question

напишіть будь ласка 9,10,11

Answer 1

$5^{2x+5} - 2^{2x+10} + 3*5^{2x+2} - 2^{2x+3} = 0|:2^{2x+2}\ 125*( frac{5}{2} )^{2x+2}-2^8+3* (frac{5}{2} )^{2x+2} - 2 = 0\ ( frac{5}{2} )^{2x+2} = t\ 125t - 256 +3t-2=0\ 128t=258\ t= frac{129}{64}\ ( frac{5}{2} )^{2x+2} = frac{129}{64} \ ( frac{5}{2} )^{2x} = frac{129}{400} \ ( frac{5}{2} )^{x} = frac{ sqrt{129}}{20} \ x = log_{2,5}frac{ sqrt{129}}{20}$

10
$2^{2x-1}+2^{2x-2}+2^{2x+2}=2^{2x-3} + 78\ 2^{2x-3}(2^2+2+2^5-1)=78\ 2^{2x-3}(4+2+32-1)=78\ 2^{2x-3}*37=78\ 2^{2x} = frac{78*8}{37} = frac{624}{37} \ 2^x = sqrt{ frac{624}{37}} \ x = log_2sqrt{ frac{624}{37}}$

11.
$5^{1+x^2}-5^{1-x^2}=24|*5^{x^2}\ 5*5^{2x^2}-5=24*5^{x^2}\ 5^{x^2} = t,t textgreater 0\ 5t^2-24t - 5=0\ D = 576+100 = 676\ t = frac{24+26}{10} =5\ 5^{x^2} = 5^1\ x^2=1\ x_1=-1\ x_2=1$

Answer 2

ну в 11 виходить 1, -1

Answer 3

без логарифмів взагалі ніяк??