Question

Как решить уравнение
(3х+1)(6-4х)=0

Answer 1

(3x+1)(6-4x)=0
14x-12x^2+6=0

D=14^2-4*(-12)*6=196+288=484

x1=(22-14)/(2*(-12))=-1/3
x2=(-22-14)/(2*(-12))=1.5

Answer 2

(3х+1)(6-4х)=0
3х+1=0 6-4х=0
3х=-1 -4х=-6
х=-1:3 х=-6(:-4)
х=-1/3 х=1,5
Ответ:-1/3; 1,5.