Question

ПОМОГИТЕ СРОЧНО!
картинка

Answer 1

$lim_{x to frac{3}{2} } frac{4x^2-9}{2x-3} = [ frac{0}{0} ]= \ =lim_{x to frac{3}{2} } frac{(2x-3)(2x+3)}{2x-3} =lim_{x to frac{3}{2} }2x+3 = 3+3=6$