Question

Помогите, пожалуйста!

Answer 1

$frac{2y}{u(u+2y)};;frac y{u(z-3u)};;frac{z+6y}{u(z-3u)+2y(z-3u)}\frac{2y}{u(u+2y)};;frac y{u(z-3u)};;frac{z+6y}{(u+2y)(z-3u)}\frac{2y(z-3u)}{u(u+2y)(z-3u)};;frac{y(u+2y)}{u(u+2y)(z-3u)};;frac{u(z+6y)}{u(u+2y)(z-3u)}\frac{2yz-6yu}{u(u+2y)(z-3u)};;frac{yu+2y^2}{u(u+2y)(z-3u)};;frac{uz+6yu}{u(u+2y)(z-3u)}\\OTBET;#4$