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(х-3)²-√5(х-3)=0
Пусть (x-3)=t, тогда:
![t^{2} - sqrt{5} t = 0
t^{2} - sqrt{5} t = 0](https://tex.z-dn.net/?f=+t%5E%7B2%7D+-++sqrt%7B5%7D+t+%3D+0%0A)
![t( t-sqrt{5}) = 0
t( t-sqrt{5}) = 0](https://tex.z-dn.net/?f=t%28+t-sqrt%7B5%7D%29+%3D+0%0A)
![t_{1} = 0 t_{1} = 0](https://tex.z-dn.net/?f=+t_%7B1%7D+%3D+0)
![t_{2} = sqrt{5} t_{2} = sqrt{5}](https://tex.z-dn.net/?f=+t_%7B2%7D+%3D+sqrt%7B5%7D)
Обратная подстановка:
![t = (x-3) t = (x-3)](https://tex.z-dn.net/?f=t+%3D+%28x-3%29)
![x_{1} - 3 = 0 = textgreater x_{1} = 3 x_{1} - 3 = 0 = textgreater x_{1} = 3](https://tex.z-dn.net/?f=+x_%7B1%7D+-+3+%3D+0+%3D+textgreater+++x_%7B1%7D+%3D+3)
![x_{2} - 3 = sqrt{5} = textgreater x_{2} = sqrt{5} + 3 x_{2} - 3 = sqrt{5} = textgreater x_{2} = sqrt{5} + 3](https://tex.z-dn.net/?f=+x_%7B2%7D+-+3+%3D+sqrt%7B5%7D+%3D+textgreater+++x_%7B2%7D+%3D+sqrt%7B5%7D+%2B+3)
Ответ:![x_{1} = 3 x_{1} = 3](https://tex.z-dn.net/?f=+x_%7B1%7D+%3D+3)
![x_{2} = sqrt{5} + 3 x_{2} = sqrt{5} + 3](https://tex.z-dn.net/?f=+x_%7B2%7D+%3D+sqrt%7B5%7D+%2B+3)
Пусть (x-3)=t, тогда:
Обратная подстановка:
Ответ:
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