Question

вычислите массовую долю элементов в AL (SO4)

Answer 1

Al2(SO4)3
w(Al) = 2Ar(Al)/Mr(Al2(SO4)3) = 54/342 = 0,16 = 16%
w(S) = 3Ar(S)/Mr(Al2(SO4)3) = 96/342 = 0,28 = 28%
w(O) = 12Ar(O)/Mr(Al2(SO4)3 = 192/342 = 0,56 = 56%

Answer 2

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