Question

Решение систем уравнений второй степени

Answer 1

$left { {{x^2-y^2=6} atop {x-y=6(x+y)}} right. left { {{(x-y)(x+y)=6} atop {x-y=6(x+y)}} right. left { {{6(x+y)(x+y)=6} atop {x-y=6(x+y)}} right. left { {(x+y)^2=1 atop {x-y=6(x+y)}} right.\ left { {{ left {[ {{x+y=1} atop {x+y=-1}} right. } atop {x-y=6(x+y)}} right. \(1) left { {{x+y=1} atop {x-y=6(x+y)}} right. left { {{x+y=1} atop {x-y=6}} right. |+ left { {{2x=7} atop {x-y=6}} right. left { {{x=3.5} atop {y=-2.5}} right.$
$(2) left { {{x+y=-1} atop {x-y=6(x+y)}} right. left { {{x+y=-1} atop {x-y=-6}} right. |+ left { {{2x=-7} atop {x+y=-1}} right. left { {{x=-3.5} atop {y=2.5}} right.$
$left[{ {{ left { {{x=3.5} atop {y=-2.5}} right. } atop { left { {{x=-3.5} atop {x=2.5}} right. }} right.$
Ответ: $(3.5;-2.5);(-3.5;2.5)$

Answer 2

неправильно