Question

$x^{2} - 3x + sqrt{5-x} = sqrt{5-x} +18$

Answer 1

$x^2-3x+ sqrt{5-x} = sqrt{5-x} +18\ 5-x geq 0\ x leq 5\ x^2-3x+ sqrt{5-x} - sqrt{5-x} -18=0\ x^2-3x-18=0\ D=3^2+4*18=9+72=81\ x_{1,2}= frac{3pm9}{2} \x_1=6\ x_2=-3\ Otvet: x=-3$