Question

(x-5)2-(y+8)2
(a+4)2-(b+2)2
(m+1)2-(n-12)2
(c-1)2-(d-23)2
Надо разложить на множители
Заранее спасибо

Answer 1

$1) (x-5)^2-(y+8)^2= (x-5-(y+8))(x-5+y+8)= \ =(x-5-y-8)(x+y+3)=(x-y-13)(x+y+3) \ \ 2) (a+4)^2-(b+2)^2=(a+4-(b+2))(a+4+b+2)= \=(a+4-b-2)(a+b+6)=(a-b+2)(a+b+6) \ \ 3) (m+1)^2-(n-12)^2=(m+1-(n-12))(m+1+n-12)= \ =(m+1-n+12)(m+n-11)=(m-n+13)(m+n-11) \ \ 4) (c-1)^2-(d-23)^2=(c-1-(d-23))(c-1+d-23)= \=(c-1-d+23)(c+d-24)=(c-d+22)(c+d-24)$