Question

sin4a-cos4a-sin2a+cos2a+1=1
помогитеее

Answer 1

sin4α-sin2α-(cos4α-cos2α)=2sinαcos3α+2sin3αsinα=2sinα(sin3α+cos3α)=0,
sin3α+cos3α=√2(sin(3α+пи/4)=0,
sin(3α+пи/4)=0,
α₁=-пи/12,
α₂=пи/4.