Question

Помогите,кто знает
3arcsin(√2/2)+2arccos1/2-4arctg1

Answer 1

3arcsin(√2/2)+2arccos(1/2)-4arctg1 = 3*π/4 + 2*π/3 - 4*π/4 = 3π/4 + 2π/3 - π = (9π+8π-12π)/12 = 5π/12