Question

Помогите пожалуйста номер 6, 7, 8. Заранее спасибо

Answer 1

$6) a) x*5^{23} = 25^{12} \ x*5^{23} = 5^{24} \ x = 5^{24}:5^{23} \ x=5^{24-23} \ x=5 \ b) x:2^{35} = 7 : 4^{17} \ x:2^{35} = 7:2^{34} \ x= 7*2^{35}:2^{34} \ x = 7*2^{35-34} \ x = 7*2=14$
$7)a) frac{3^7*(3^5)^3}{3^{21}} -3^1 = 3^{7+15-21}-3 = 3-3=0 \ b) frac{15^3}{5^4*9}= frac{5^3*3^3}{5^4*3^2} = 5^{3-4}*3^{3-2} = frac{3}{5} = 0.6 \ c) (frac{7}{9})^{13}*(1 frac{2}{7} ) ^{14}= (frac{7}{9})^{13}*(frac{9}{7} ) ^{14} = (frac{9}{7})^{-13}*(frac{9}{7} ) ^{14} = ( frac{9}{7} )^{14-13} = frac{9}{7}$
$d) (1.5)^7*( frac{2}{3} )^6*(2.(3))^{25^3-5^6} =( frac{3}{2} )^7*( frac{2}{3} )^6*(2 frac{1}{3} )^{5^6-5^6} = \ = ( frac{2}{3} )^{-7}*( frac{2}{3} )^6*(2 frac{1}{3} )^0= (frac{2}{3}) ^{6-7}*1 = frac{3}{2} = 1.5$
$8.(2^2)^2 = 2^4 \ 2^{2^2}= 2^4 \ 2^{2^2}; (2^2)^2;222; 22^2;2^{22}$