Question

Найдите область значений функции: y=6-3sin2x

Answer 1

y = sinx   [ -1; 1]
y = sin2x  [ - 1; 1]
y = 3sin2x [ - 3; 3]
y = - 3sin2x  [ - 3; 3]
y = 6 - 3sin2x   [ 3 ;  9]