Question

помогите
cos^2x-sin^2x=√3/2

Answer 1

cos²x-sin²x=√3/2
cos2x=√3/2
2x=π/6+2πn⇒x=π/12+πn,n∈z
2x=-π/6+2πn⇒x=-π/12+πn,n∈z