Question

ПОМОГИТЕ ПЖ,напишите решение на листе.#245

Answer 1

$frac{a-2b}{5b+3a} =5; ; ; Rightarrow \\frac{4b-2a}{5b+3a} = frac{-2(a-2b)}{5b+3a} =-2cdot 5=-10\\\ frac{5a-10b}{15b+9a} = frac{5(a-2b)}{3(5b+3a)} = frac{5}{3}cdot 5=frac{25}{3}\\\ frac{a^2-4ab+4b^2}{9a^2+30ab+25b^2} =frac{(a-2b)^2}{(3a+5b)^2} =(frac{a-2b}{5b+3a})^2=5^2=25$


$frac{2a^2b^2-a^3b}{6a^3b+10a^2b^2} =frac{a^2b(2b-a)}{2a^2b(3a+5b)}=frac{-(a-2b)}{2(5b+3a)}=-frac{1}{2}cdot 5=-2,5\\\ frac{15b^4+9ab^3}{ab^3-2b^4} =frac{3b^3(5b+3a)}{b^3(a-2b)}=frac{3}{frac{a-2b}{5b+3a}} =frac{3}{5}=0,6\\\ Big (frac{5b+3a}{2b-a}Big )^3=Big (frac{-1}{frac{a-2b}{5b+3a}}Big )^3 =frac{-1}{5^3}=-frac{1}{125}=-0,008$