Question

помогите пожалуйста очень надо

Answer 1

$4x^2-3x=0 \ x(4x-3)=0 \ left { {{x=0} atop {4x-3=0}} right. \ left { {{x=0} atop {x= frac{3}{4}=0.75 }} right. \ OTBET:0; 0.75 \ \ frac{6x-1}{5} - frac{2-x}{4} = frac{3x+2}{2} \ frac{24x-4-10+5x-30x-20}{20}=0 \ -x-34=0 \ x=-34 \ OTBET:-34$

$2x^2-5x=0 \ x(2x-5)=0 \ left { {{x=0} atop {2x-5=0}} right. \ left { {{x= frac{5}{2} = 2.5 } atop {x=0}} right. \ OTBET:0;2.5 \ \ frac{2x-3}{6} - frac{4-x}{3} = frac{x-1}{2} \ frac{2x-3-8+2x-3x+3}{6} =0 \ x-8=0 \ x=8 \ OTBET:8$