Question

математика 5 сынып атамура
1270есеп
(6,1/8-1,75)÷(9-2,2×(5,6/11-3,5))×1,2/7=
ондык болшектерди жай болшекке айналдырып алып, амалдарды орындандар.

Answer 1

(6,1/8-1,75)÷(9-2,2×(5,6/11-3,5))×1,2/7= (6,1/8- 1,3/4):(9-2,1/5*(5,6/11-3,1/2))*1,2/7= (6 1/8-1 6/8):(9-2 1/5*(5 12/22-3 11/22))*1 2/7= 4 3/8:(9-2 1/5* 2 1/22)*1 2/7= 4 3/8:(9-11/5*45/22)*9/7= 35/8:(9-9/2)*9/7= 35/8:(18/2-9/2)*9/7= 35/8:9/2*9/7= 35/8*2/9*9/7= 35/36*9/7 = 5/4= 1 1/4