Question

Найти производную y=√x^2+1/x
Y=(cos3x+6)^2
Y=(x^3-4x^2)^16

Answer 1

        
y'=(u/v)'=1/v²[u'v-v'u]   u=√(x²+1)  u'=1/2√(x²+1)
                                    v=x   v'=1
y'=1/x²[x/√(x²+1)-√(x²+1)]
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y'=2(cos3x+6)*(-sin3x)*3
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y'=16(x³-4x²)^15*(3x²-8x)