Question

(x-2)(3+1)(4x-3)
(m-5)(m-1)-(m+2)(m-3)
(a-1)(a-2)+(a-3)(a-4) при a=0,2
(3a-2b)(9a^2+6ab^2+4b²)

Answer 1

1) (х-2)(16х-12)=16х^2-12х-32х+24= 16х^2-44х+24=4х^2-11х+6
D=121-4*4*6=25
x1=11+5/2*4=2
x2=11-5/2*4=0,75